a 44.6 g of iron ore is treated as follows. the iron in the sample is all converted by a series of chemical reactions to Fe2O3. the mass of fe2O3 is measured to be 10.1 g.what was the % iron in the sample ore?
mol mass / molar mass mass Fe2O3 10.1g. molar mass Fe2O3 159.69 g/mol. atomic wt Fe2 55.8 * 2 111.6 g/mol. (111.6 / 159.69) * 10.1 7.06 g Fe. (7.06 / 44.6) * 100 15.83% iron in the ore.
the type of car would help but what it sounds like is a power steering rack or gear box that is loose or broken off from its brackets. so when you turn the wheel the whole rack is moving back and forth reducing your turn radius. usually tie rods, drag links and pitman arms will cause a slop in the steering as well as clunks but not much for reduced turning radius. (unless they are broken)
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% by mass of Fe2O3 (mass of organic Fe2O3 / mass of iron ore) x a hundred% mass of Fe2O3 (organic) (mass of iron produced / MW of iron) x ( stoichiometric mole ratio of Fe2O3 over Fe based on the given chemical reaction x MW of Fe2O3 mass of iron produced 453 g MW of Fe fifty 5.80 5 stoichiometric mole ratio of Fe2O3/Fe a million/2 MW of Fe2O3 159.7 mass of organic Fe2O3 (453/fifty 5.80 5) x (a million/2) x 159.7 mass of organic Fe2O3 647.sixty six grams %by mass of Fe2O3 (647.sixty six / 752) x a hundred 86.13 %
the type of car would help but what it sounds like is a power steering rack or gear box that is loose or broken off from its brackets. so when you turn the wheel the whole rack is moving back and forth reducing your turn radius. usually tie rods, drag links and pitman arms will cause a slop in the steering as well as clunks but not much for reduced turning radius. (unless they are broken)
Jessica, I want you to listen to these words. If it has to do with Brakes, Suspension or Steering, Yahoo Answers is not the place to be risking your life on a couple of guesses. If your car all a sudden has sloppy steering, then you need to all a sudden go see a reputable mechanic. Chances are your centerlink or tierods have play, any vehicle with around 100K miles on it should be ready for these parts. But do not wait, If you are on the highway and any of these parts finally let go. You'll be in life threatening danger!
% by mass of Fe2O3 (mass of organic Fe2O3 / mass of iron ore) x a hundred% mass of Fe2O3 (organic) (mass of iron produced / MW of iron) x ( stoichiometric mole ratio of Fe2O3 over Fe based on the given chemical reaction x MW of Fe2O3 mass of iron produced 453 g MW of Fe fifty 5.80 5 stoichiometric mole ratio of Fe2O3/Fe a million/2 MW of Fe2O3 159.7 mass of organic Fe2O3 (453/fifty 5.80 5) x (a million/2) x 159.7 mass of organic Fe2O3 647.sixty six grams %by mass of Fe2O3 (647.sixty six / 752) x a hundred 86.13 %
mol mass / molar mass mass Fe2O3 10.1g. molar mass Fe2O3 159.69 g/mol. atomic wt Fe2 55.8 * 2 111.6 g/mol. (111.6 / 159.69) * 10.1 7.06 g Fe. (7.06 / 44.6) * 100 15.83% iron in the ore.
Calculate the mass of Fe in 10.1g Fe2O3 Molar mass Fe2O3 159.7g/mol Molar mass Fe 55.85: 2Fe 111.7g Mass Fe in 10.1g Fe12O3 10.1*111.7/159.7 Mass of Fe 7.064g 44.6g ore contained 7.064g Fe % Fe in ore 7.064/44.6*100 15.84% Now you have two answers that agree - take your pick.
Calculate the mass of Fe in 10.1g Fe2O3 Molar mass Fe2O3 159.7g/mol Molar mass Fe 55.85: 2Fe 111.7g Mass Fe in 10.1g Fe12O3 10.1*111.7/159.7 Mass of Fe 7.064g 44.6g ore contained 7.064g Fe % Fe in ore 7.064/44.6*100 15.84% Now you have two answers that agree - take your pick.
