What would the additive and multiplicative inverse of 2 be and how do you solve this?
Additive inverse is -2 Multiplicative inverse is 1/2 You get the additive inverse of a number by multiplying it by -1. You get the multiplicative inverse of a number by dividing 1 by the number.
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it depends in what ring. in N ,2 doesnt have an additive inverse, in Z the additive inverse of 2 is -2, in Z/3 it is 1 multiplicative idem dito in N, Z none, in Q it is 1/2 , in Z/3 it is 2 itself. greetings.
To find an inverse of a number, you first need to decide what the identity is, for that operation. Considering addition, what number x satisfies the following: a + x a. Clearly its 0, so the identity is 0. Considering multiplication, what number x satisfies the following: ax a The answer is 1, so the identity is 1. Now, the inverse x of a number a is s.t a * x e, . . where * is the operation (addition, multiplication.) and e is the identity. So, for addition, a + x 0 The inverse x will be -a. For multiplication, ax 1 The inverse x will be 1/a. Since in your question a 2, the additive inverse is -2 and the multiplicative inverse is 1/2.
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