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Question:

When 0.058 mol of aluminum sulfate are dissolved in enough water to make 385 milliliters of solution, what is?

When 0.058 mol of aluminum sulfate are dissolved in enough water to make 385 milliliters of solution, what is the molar concentration of aluminum ions?Answer in units of M.

Answer:

0.058 moles Al2(SO4)3 / 0.385 Litres 0.1506 Molar Al2(SO4)3 since there are 2 moles of Al in 1 moles of Al2(SO4)3 0.1506 Molar Al2(SO4)3 releases twice that in Al+3 0.3012 Molar Al+3 your answer rounded to the 3 sig figs in 385 milliliters of solution is 0.301 Molar Al+3 however there are only 2 sig figs showing in 0.058 mol of aluminum sulfate your answer rounded to 2 sig figs would be 0.30 Molar Al+3

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