When 0.084 mol of aluminum sulfate are dis-solved in enough water to make 711 millilitersof solution, what is the molar concentrationof aluminum ions? Answer in units of M.
Hey! Molarity(M) is moles of solute per Liters of solutionSo, first off, we have to convert 711mL to LThis is done by dividing 711mL by 1000 to get LSo, that would be 0.711LNow to find MolarityWe take the moles of solute, 0.084 mol ammonium sulfate, and divide it by the Liters of solution, 0.711LMolarity0.084mol/0.711L Molarity0.11814346 Now, this number has to be rounded to the correct number of significant digitsWe can find this by seeing that 0.711 has 3 sigdigsand 0.084 has only 2, and, since we round to the least amount of sigdigspresent, we round to 2 significant digitsSo, the final answer is 0.12MHope this helps!
