When a small AC motor is operating at rated load from a 115V, 60-cycle source, it takes 287 watts at a lagging power factor of 0.6. a. Calculate the line current. b. What should be the capacitance of the capacitor connected in parallel with the motor that will make the power factor unity?. c. Determine the line current under this condition?
Power, p = 287 watts, power factor 0.6(lagging 53.1°) volts, v = 115 volts, 1.) line current, IL = 287/115 = 2.5 Amps 53.1° lagging >==================< ANSWER 2.) Impedance, |z| = (115)^2/287 = 46.1 ohms, OR, z = 46.1(cos53.1° - j.sin53.1°), SO, Reactance, XL = -46.1*sin(53.1) = 36.86 ohms, For unity power factor, Capacitor C ?F is connected, SO, 1/2pi f C = 36.86, ===> C = 1/2pi*60*36.86 = 0.72 ?F >===============< ANSWER
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