The hot button is Avogadro' number which is 6.0226 x 10^23 atoms per mole So if the fee of the Al roll is $2.Fifty two for one lb Then proceed as follows: 1 lb 454 gms At Wt Al 26.Ninety eight gms per mole Moles of Al in 1 lb 454/26.Ninety eight sixteen.82 moles number of atms of Al sixteen.Eighty two x 6.0226 x 10^23 1.013 x 10^25 fee per atom $2.52 / 1.013 x 10^25 $2.2847 x 10^-25 per atom or zero.0000000000000000000000228 cents per atomBTW, you failed to full specify the trouble - how thick is teh Al foil? In any occasion Al atoms are pretty low pricedHope this helps
Aluminum has 3 valence electronsLoosing 3 negative charges leaves behind an Al+3 The answer is C+3
