When the inverter is running at full 50HZ, the output voltage decreases and the output current becomes smaller. What is the reason?
However, when the frequency is raised, the current will decrease if the load is not large, especially when the motor is idle. The magnitude of the current is determined by the load. If you can add some load, you will see the current rise. Speaking of principles, can be understood as the motor is a big inductance, when the power frequency increases, the motor impedance Z will become larger, the impedance is large, the voltage is constant, the flow of the current will naturally be small,
If the load of the motor is increased, the slip S is increased, the electromotive force of the motor is decreased, and the electric current of the motor will become larger. That is to say, when the motor is running in the overclocking stage, the load of the motor is light, the current will become smaller, and the current will not be smaller if the load is negative. Didn't I make myself clear?
I don't know if you're a manufacturer of car gearboxes, and we've also done car engine tests. The operation in the 50HZ when the inverter is not reduced voltage, if only a little decrease will decrease, this is due to increasing frequency, controllable silicon resistance increases, the corresponding motor voltage decreased slightly, not what the essence of influence.
