What I get is the following:If switch 1 is on light 1, light 2 and light 3 are on. Switches 2 and 3 off.If switch 2 is on light 2 and light 3 are on. Switches 1 and 3 off.If switch 3 is one light 4 is on. Switches 1 and 2 off. Am I correct or am I missing something? Any tips and help appreciated. Please explain.Thank you!
If switch 1 is on then lights one two and three are definitely on no matter what the position of the other switches. Light four MAY be on depending on S3 Your answer is correct. If switch 2 is on then lights two and three are definitely on. And as long as S1 is off L1 will remain off. Your answer is correct. If switch 3 is on then lights 3 and four both must be on. The diode passes current from light 4 to light 3 so your answer is wrong. Note that the circuit is additive. Turning any switch on may turn on extra bulbs but cannot turn off any bulb that is already alight. So switch 2 and 3 together have all lights on except L1 Switch 1 and 3 together have all lights on. Whether or not switch 2 is on.
If switch 3 is one light 3 AND light 4 is on. Switches 1 and 2 off. Note the polarity of the diode between 3 4.
Your flickr link doesn't work anymore.
Any circuit: Draw the circuit with the switches set the way you want to test Start at the + of the source and draw a line through the circuit elements. You cannot cross an open switch. If any path exists that will allow you to return to the - of the source, all lights you pass through will be lit. If you cannot find a complete path through a light, it will not be lit. If you cannot do it in your head, do it with a pencil
