(1) Aluminum is malleable. (2) Aluminum reacts with sulfuric acid.(3) Aluminum conducts an electric current.(4)Aluminum has a density of 2.698 g/cm3 at STP.Explain why.
The answer is statement 2 Reasons why: First, know that a chemical property of any element is something that results in the change of the chemical make-up of the element. The word for word definition in my textbook says: a chemical property is the ability of a substance to combine with or change into one or more substances through a change in the chemical formula for the substance Looking at all the other options: Statement 1: Whether or not a substance is malleable is whether or not a substance can be hammered or pressed out of shape and not break or shatter. Hammering a substance, or in this case Aluminum, does not change any chemical formula of Aluminum, it just changes the physical shape of the metal. Statement 3: If a substance is conductive of electricity, it means that the material can transport an electric current. This is not chemical because the electricity simply goes through the substance, it does not change or react with any of the atoms of a substance and change the chemical formula. Statement 4: Density is a purely physical property because it is how dense a material is, and it doesn't change the formula of a substance. Therefore, Statement 2 is the best answer because by reacting with sulfuric acid, the chemical formula of aluminum changes since the atoms recombine with the atoms of sulfuric acid and create a new substance and a new chemical formula with it.
oxygen supports combustion is the chemical one
statement 2 because it describes the nature of a reaction involving aluminium. The reaction is governed by its chemical properties such as the number of electrons is contains and its ability to for ions.
The answer is choice 2. Why? It's the only one that describes a chemical interaction. The other three describe physical properties of aluminum, that is properties that do not involve a change in the chemical identity of aluminum metal. In choices 1, 3, and 4, the aluminum metal remains as aluminum metal. However, in choice 2, the metal reacts and becomes aluminum ion.
