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Question:

Why is the loss 3 electrons in aluminium easier than the loss of 2 electrons?

3s^2 3p^1 -gt; 3s^0 3p^0

Answer:

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The energy required to remove two electrons in an aluminium orbital is lesser than that required to remove threeI won't give you the vlues,but I'll try to explain in a logical wayAn atom has electons and protons of equal and opposite chargeThe latter, being positve and the former negativeThes are balnced in number ie, the number of protons number of electrons in an atomThat means that, the moment you remove one electron on the outer shell, you have caused an imbalanceBut that's not where I am goingThere are attractive forces these particles exert on each other in equal measureWhen 1 electron exerts a force of 1Newton, (which is the same as a proton's), 13 elecetrons would exert a force of 13N which balances 13N attractive forces exerted by the protons in the nucleusIf you remove on electron, you are left with 13 protons against 12 electronsthe energy that is required the next most loosely bound electron (the second ionization energy) will be more than the first you used, because there is more attarctive force exertedThe trend increases as you remove more elctrons In summary, you are required to exert more energy when removing more than one electronThank you
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