You have a 3 foot wide wire, vs a .3 inch wire. They are equal length. There is 3 volts going through each wire, to power your 1 volt LED. So, would the 3 foot wide wire have less resistance ? I don't even think it would work.
Increasing the diameter of a wire while maintaining a constant density is equivalent to connecting another wire in parallel with the present wire. Each wire contains a certain end to end resistance. The total equivalent end to end resistance of two wire resistors connected in parallel is always less than resistance value of the wire with the smallest end to end resistance. Another way to look at it. The larger the wire the greater the cross sectional area. The greater the cross sectional area of a wire the greater the number of parallel paths the current can take. The more parallel current paths available from one end of a wire to the other the less the overall resistance of the wire will be. You stated There is 3 Volts going through each wire, to power your 1 Volt LED. If this is true then you must have a resistor of roughly 100 Ohms that is dropping 2 Volts connected between the 3 Volt source and the 1 Volt LED. Either the 3' wide wire or the .3 wire would work fine in this application. The .3 wire would be a tad less cumbersome than the 3` wire I might add. Response to additional details: Conductance is the reciprocal of resistance and is independent of the applied Voltage. More length of a given wire would mean more resistance. More cross sectional area of a given wire means less resistance. Any wire has resistance but the conductor wire resistance itself in an LED circuit is of no consequence I believe.
You have to study more. Fist, voltage does NOT go through a wire. If you can find a 3 foot diameter wire (what I think you mean by wide), that would be a huge wire. And yes, it has a much lower resistance than a 0.3 inch diameter wire. But for one LED, it won't make any difference, either will behave as well, in fact you can use a much smaller wire than 0.3 inch, as that is quite large as wires go. You can probably use a 0.01 inch wire and it will work fine.
Because there are a lot more electrons available in that ridiculously large wire.
'sure` bigger wires have decrease resistance. 'No' on the transformer component of your question. With the transformers, 'magnetic saturation` performs a substantial section in cutting-edge limiting. The impedance of a transformer isn't in effortless terms resistance. Google or Wiki 'Choke coil'
When I started out, I found that the water analogy was helpful. Water flow (through a pipe) represents the electrons flowing (= current). The pipe represents the wire. It's hard to push a high flowrate of water through a small pipe (say like a drinking straw), but easy through a large-diameter pipe. The small pipe shows high resistance to flow, the large pipe shows little resistance to flow. Electrical current works the similarly, for electrons flowing through the wire. In electrical circuits, voltage corresponds to pressure. Are you aware that to push 1A through a wire of resistance 1 ohm requires a voltage drop across the wire of 1V? And that if you increase that voltage to 2V (from 1V), twice the current will flow (=2A), even though the resistance stays the same? If you had two of those wires (connected in parallel), you could push 1A through each wire by applying 1V across each wire. That would total 2A without having to increase the voltage. Well, that essentially is what a larger-diameter wire is, it's the equivalent of taking two (or more) smaller wires and melding their cross sections together into that of a single wire. But since it now takes only 1V to push 2A instead of 2V, it appears that the resistance is half as much, as in 0.5ohms, when using both wires. From that you can conclude that larger-diameter wires have lower resistance. Hope that helps. Later you will discover that the water analogy doesn't match perfectly well since its pressure relationship is highly non-linear, whereas the electrical relationship tends to be highly linear. Also, we generally don't push water back-and-forth in pipes the way some electrical circuits use alternating current. That's a heads-up that the water analogy will fail to explain some of the electrical things you'll run into.
