Wire 1 and wire 2 are made from the same metal. Wire 2 has a larger diameter than wire 1. The electric field strengths E1 and E2 are equal. A) Compare the values of the two current densities. Is J1 greater than, less, or equal to J2?B) Compare the values of the currents I1 and I2. Is I1 greater then, less or equal to I2?
The current will be more dense in the smaller wire. The value of the current is inversely proportional to the resistiance of the wire. Resistance = resistivity * length / Area since the wires are of identical material and length, the only thing left to vary is the cross-sectional area. Area is proportional to the square of the radius (diameter), so the current will be proportional to the square of the diameter. I2 is proportional to I1^2 I2 is larger than I1 .
