With copper as the anode and graphite as cathode, dilute sulfuric acid as electrolyte in electrolytic electrolysis, why early, the cathode is H+ first discharge?Is not copper ion?
This is what you say:The anode is Cu and is the active anode, so the electrode reaction is Cu-2e- =Cu2+ cathode reaction: 2H++2e-=H2However, as the copper ions move to the cathode, the copper ion will preferentially discharge from the hydrogen ion, so the cathode reaction is: Cu2++2e-=Cu
Cathode: a discharge of cations (discharged in the order of oxidation, i.e., in the reverse order of activity of metals)Anode: first, the active electrode (silver and the metal before), and then the anion discharge (in the order of reduction)This is what you say:The anode is Cu and is the active anode, so the electrode reaction is Cu-2e- =Cu2+ cathode reaction: 2H++2e-=H2However, as the copper ions move to the cathode, the copper ion will preferentially discharge from the hydrogen ion, so the cathode reaction is: Cu2++2e-=Cu
Cathode: a discharge of cations (discharged in the order of oxidation, i.e., in the reverse order of activity of metals)Anode: first, the active electrode (silver and the metal before), and then the anion discharge (in the order of reduction)
