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Question:

A current in a 100uH inductor is known to be i(L) 20te^-5t for t>0. Can you show me how you got the answer?

A current in a 100microH inductor is known to be i(L) 20te^-5t for t 0A) Find the voltage across the inductor for t0. (Assume the passive sign convention)B) Find the power (in microwatts) at the terminals of the inductor when t100ms.C) is the inductor absorbing or delivering power at 100ms?D) Find the energy (in microjoules) stored in the inductor at 100ms.

Answer:

I don't have time to check the work, but here is the general idea. i(l) integral [v(t) dt], in this case, for t0 i 20te^-5t is given A) e(t) voltage across the inductor Ldi/et L20[ e^-5t(dt/dt) + t d(e^-5t)dt] L20[e^-5t + t(-5e^-6t)] (20 e^-5t)(1 - 5te^-t) B) Power e(.1) times i(.1) C) Absorbing, since e(.1) is still positive D) E (1/2) Li(.1)^2

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