A load of lumber of weight W 25 kN is being raised by a mobile cranePLEASE HELP!!! Picture Included?
I've never mastered handling this materialI've been at it weekly for 40+ years.
Do moments sum at H: taking a clockwise rotation as positive: -25(2.9)-3Kn(.9)+50Kn(2)+Rk(2.5)0 Isolate Rk: Rk(25(.9)+3(.9)-50(2))/2.5-29.92 (this is in the two back wheels, so divide by two) Rk1,Rk2-14.96 (assuming a perfectly centered load) for the reaction on H do a vertical sum of forces taking down as positive: 25+3+50-Rh-14.960 Rh 63.04 Divide by two Rh1,Rh2 31.52Kn So if I was the driver I'd consider jumping shipHope this helps.
