find the inductive reactance of the inductor if there are 240 mA of current flowing through it and 1.44 x 10 negative 4 joules of potential energy stored inside its magnetic field.
Potential energy in an inductor is equal to (1/2)Li^2. Solving for L with algebra will give you the inductance. 1.44 x 10^-4 (1/2)L(.240)^2 L .005 henrys Inductive reactance is simply given by X wL. Since w 2(pi)f, plug in 120 Hz for f and get w 240pi. So X 240pi(.005) 1.2 pi 3.77 ohms reactive
