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Question:

Faradays law characterizes the voltage drop across an inductor asVL L di/dt?

Faradays law characterizes the voltage drop across an inductor asVL L di/dt where VL voltage drop (V), Linductance (in henrys; 1 H 1 V s/A), i current (A), and t time (s). Determine the voltage drop as a function of time from the following data for an inductance of 4 H

Answer:

Use VLL di/dt. You should be able to figure out what di and dt are for each interval.
OK, so I (0) 0, I(0.1 s) 0.16A, I(0.2 s) 0.32A, I(0.3 s) 0.56A, I(0.5s) 0.84A, I(0.7 s) 2.0A. It doesn't seem that dI/dt is constant or linear; I'm going to approximate it as a set of point values: dI/dt (0.05 s) 1.6 A/s, dI/dt (0.15 s) 1.6A/s, dI/dt (0.25 s) 2.4 A/s, dI/dt (0.40 s) 1.4A/s, dI/dt (0.60 s) 5.8 A/s. So V(t) looks roughly like this: V(0.05 s) 6.4 V, V(0.15 s) 6.4 V, V(0.25 s) 9.6 V, V(0.40 s) 5.6 V, V(0.60 s) 23.2 V.

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