I have simple rl circuit two resistance in parallel and a inductor - 5 H in parallel. I need to thevenize the circut but I do not know how to handle with the inductor, wich is in value of 5 Hplease help thank you
RF and 5Henry inductor does not seem to go together. ANyway, R of an inductance can be measured by an ohm meter. I guess what you need is XL which is 2.pi.f.L. Calculate this at the frequency of your choice. Then if an R is across it, the parallel impedance is |RZ/(R+Z)|, where Z j*2.pi.f.L. If XL denotes 2.pi.f.L, then Z jXL, and parallel impednace is R*XL/sqrt(R^2+XL^2)
let's see what we can find :-) (by the way, what does thevenize mean? I've never heard of that before)
