Home > categories > Minerals & Metallurgy > Aluminum Foils > If I wanted to get exactly 2 x 10^27 aluminum atoms, how many grams of foil would I need? Calculate.?
Question:

If I wanted to get exactly 2 x 10^27 aluminum atoms, how many grams of foil would I need? Calculate.?

If I wanted to get exactly 2 x 10^27 aluminum atoms, how many grams of foil would I need? Calculate.?

Answer:

its not a stupid question, your not supposed to blow dry it cuz yes it will burn your head
It shouldn't burn your head, just don't use the hair dryer right on your scalpMove it all over your head so that it doesn't stay in one place too long.
The foils wont burn your head but if you hold the blow dryer to close than the blow dryer will burn your head I have colored my hair many times so I would know.
1Take the amount of atoms you need (2x10^27) and divide by Avogadro's Number (6.02x10^23)Should get 3,322.26 moles of Aluminum 2Multiply the number of moles you have (3,322.26) by the molar mass of aluminum (26.98 g)The answer is 89,634.57 grams of aluminum 3Round to appropriate amount of sig figs.

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