A 0.595 H inductor is connected in serieswith a ?uorescent lamp to limit the currentdrawn by the lamp.If the combination is connected to a57.3 Hz, 93.5 V line, and if the voltage acrossthe lamp is to be 26.9 V, what is the currentin the circuit? (The lamp is a pure resistiveload.)Answer in units of A.Please help!!!!
Calculate inductive reactance by formula X(L) 2 (pi) f L 2 *3.14 * 57.3 * 0.595 214.57 ohm Applied voltage 93.5 v. By Kirchoff;s law, this equals voltage drops in R and XL I*XL + I*R93.5 But these 2 voltages have phase difference of 90 deg so they must be added vectorially we know I*R 26.9 I*XL (93.5 ^2 -26.9^2)^0.5 i*XL89.54 i89.54/214.57 0.41733 Amp
