After the switch in the following circuit has been closed for a long time (tinfinity), what is the current through L1?Also, after the switch in the circuit in the circuit has been open for t500 microseconds, what's the current through L2?How do i find the current? Please show me or give me instructions how as this will help me in the future.
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The current through L1 and L2 after S1 has been closed a long time is 20 milliamps, (10v/ 500 Ω). 10 (L1 + L2) di/dt + (R1 || R2)i 10 0.250(di/dt) + 500i When S1 is opened 10 0.250(di/dt) + 1,000i with i initial 20 milliamps i 10(e^-t/τ) +10 milliamps where τ L/R 250 millihenry/1,000 250 microsecond after 500 microseconds which is 2 τ i 10e^-2 + 10 1.35 + 10 13.5 milliamps
the current initially is 10v / 500 ohms 0.02 amp When you open the switch, the current will eventually decrease to 10v / 1000 0.01 amp It decays exponentially from the initial to the final value with a time constant, T, of L/R 0.25 / 1000 250 usec i(t) 0.01 + 0.01 e^(-t / T) i(500) 0.01 + 0.01e^(-500/250) 0.01 + 0.01e^(-2) 0.01135 amp
