The volume of a silo is V=2500*pi*sin(θ). Assuming the original value of θ is pi/2, what angle θ is required to bring the original volume of the silo down by 2%?
sin π/2 = 1, so the orig. value of V is 2500*π. Reducing volume by 2% gives V = 2450*π So 2450*π = 2500*π*sin(θ), ie sin(θ) = 2450/2500 ≈ 0.98 taking inverse sign gives θ = 1.37 radians, or 78.5 degrees
