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2 Al (s) + 6 HCl (aq) → 3 H2 (g) + 2 AlCl3 (aq).?

Hydrochloric acid reacts with powdered aluminum according to the reaction:2 Al (s) + 6 HCl (aq) → 3 H2 (g) + 2 AlCl3 (aq)What volume of hydrogen gas (in L), measured at 884 mmHg and 30.9 °C, is required to completely react with59.87 g Al? Assume the amount of hydrochloric acid present is in excess.Please show work!

Answer:

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Stoichiometry Use the unit-factor method2Al(s) + 6HCl(aq) - 2AlCl3(aq) + 3H2(g) 59.87g excess ?L (884 torr and 30.9C) 59.87g Al x (1 mol Al / 26.98g Al) x (3 mol H2 / 2 mol Al) 3.329 mol H2 PV nRT V nRT / P V 3.329 mol x 62.36 Ltorr/molK x 304.05K / 884 torr) V 71.4 L rounded to three significant digits

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