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Question:

240 V at 50 Hz applied to an inductor yields a current of 4A calcuate the maximum stored energy during a cycle?

A voltage of 240 V at 50 Hz applied to an inductor yields a current of 4 A. calculate the maximum stored energy during a cycle, and the average power.is the maximum stored energy 0 or 1.52 ?

Answer:

Assuming the current is 4 amps RMS the impedance is j60 ohms, so the inductance is .191 H. The peak current is 1.414*47.07 amps The peak store energy is .5 L Ip^24.77 joules. There is 0 average power consumed by a lossless inductor.

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