Can anyone help me with this problem? I thought that the answers are zero for the inductor and the resistor. Thanks!!!!!!!!!!!!!An AC source operating at 59 Hz with a maximum voltage of 170 V is connected in series with a resistor (R 1.2 kilo-ohms) and an inductor (L 3.8 H). ΔVR, max 110 V and ΔVL, max 129 V. The max current is 0.092A. When the current is zero What are the potential differences across the resistor, inductor and AC source?
For a correct working of this Google, Inductive Reactance, and plug in your values.
Edit: After some thought I have changed my answer to the following. I believe that when the instantaneous current is zero then; 1. The potential Voltage difference across the resistor is equal to zero. 2. The potential Voltage difference across the inductor is equal to 129 Volts. 3. The potential Voltage across the source Voltage is equal to 129 Volts . I assumed you are talking about instantaneous current because the rms AC current will never go to zero as long as the 59 Hz source Voltage is connected. Here is my reasoning for the above answers and there is no guarantee that the answers are correct. When the instantaneous current through the resistor goes to zero as it must do once during each source voltage half cycle then at that point in time, since V of R and I of R are always in phase with each other, V of R must be zero because V of R IR and the instantaneous value of I is zero at this time. The inductor acts as a source Voltage at times during each cycle and changes Voltage polarity each time it switches from dropping a Voltage to supplying a Voltage. Now if there is no current through the resistor that means that what ever Voltage the source is supplying at that time on one side of the resistor must also be being supplied on the other side of the resistor by V of L. From this we can say that anytime I of R equals zero then V of source must equal V of L. The instantaneous value of V of L L di/dt. When V of L reaches maximum 129V ( I) becomes zero and reverses directions. At this point in time The instantaneous source Voltage has decreased from it`s maximum down to an amplitude equal to V of L (129V). This would put 129V on each side of the 1.2 k Ohm resistor and thus account for zero current through it at this particular time.
