27.0 g of aluminum metal are heated to 98.0°C and then placed in a perfectly insulating container along with 199.0 g of water at an initial temperature of 20.10°CAfter a short time the temperature of both the metal and water become equal.The specific heat of water is 4.18 J/g/K.The specific heat of aluminum metal is 0.908 J/g/K.What is the final temperature in °C?
i would recommend that you replace the heater matrix.its not a straight task.it would be best to let a mechanic do the job.
I've saved lots of cooling systems with the likes of Aluma-Seal and other similar productsYou can try it if you want to but usually heater cores have such small passages that the leak stop product just plugs them upThe leak gets fixed but coolant flow through the core is restricted or non-existent.
In this problem heat leaves the metal and enters the water(Kelvin degrees are the same size as Celsius degrees.) The heat that leaves is given the negative sign in the following equation: -q q -[(mass of metal)(specific heat of metal)(change in temperature of metal)] [(mass of water)(specific heat of water)(change in temperature of water)] -[(27.0 g)(0.908 J/g.C)(Tf - 98.0C)] [(199.0 g)(4.19 J/g.C)(Tf - 20.10C)] (-24.516 J/C)(Tf - 98.0C)] (831.82 J/C)(Tf - 20.10C) -24.516 J/C (Tf) + 2402.568 J 831.82 J/C (Tf) - 16719.582 J 2402.568 J + 16719.582 J 831.82 J/C (Tf) + 24.516 J/C (Tf) 19122.15 J 856.336 J/C (Tf) 22.330195 C Tf 22.3 C Answer: The final temperature of the mixture is 22.3 degrees Celsius
