32g what is the diameter of the stainless steel ball?
Because 201, 202, 301, 302, 304, 304L, 305, 310, 321, stainless steel has a density of 7.93 g / cubic centimeterAccording to the mass formula of matter, m=pV can be seenThe size of 32g stainless steel ball is V = m/p = 32/7.93 = 4.04 (cubic centimeter)
According to the volume formula of the ball, V=4*TT*R*R*R/3 can be seenThe radius of the 32g stainless steel ball is cubic R*R*R = 3V/ (4*TT) = 3*4.04/4*3.14 = 0.97 (cubic centimeter)So the radius of stainless steel ball is R = 0.99 (CM)The radius of the stainless steel ball is D = 2R = 2*0.99 (CM) = 1.98 (CM)
