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Question:

A 117 V, 60 Hz, AC line is connected across a resistance of 1000 ohm, which is in parallel with an inductor of?

5.00 H. Find the current through the resistor, inductor, and the total current in the circuit.

Answer:

Actually you should specify the resistance of the 5 H inductor, but in this case X(L)R so the impedance can be estimated as the inductive reactance, where 5 H @ 60hz by X(L)2piFL6.28*60*5 1884 ohms. Resistor current equals 117/1000 .117 A. Inductor current 117/1884 .062A

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