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Question:

A 165N rock is hoisted upward with an acceleration of 1.56m/s^2 by a vertical chain of negligible weight.?

What is the tension in the bottom link of the chain?What is the tension in the middle link of the chain?

Answer:

F = m*g + m*a let W be the 165 N weight, W = m*g, m = W/g F = W + (W/g)*a F = 165 + (165/9.8)*1.56 F = 165 + 26.3 = 191.3 N The tension in the bottom link and the middle link are the same since the chain is of negligible weight.

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