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Question:

A 2 AWG aluminum conductor is 450 ft longwhat is the resistance of the wire?

please show calculations with formula

Answer:

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Well, it's impossible to answer the question with 100% accuracy based on the provided informationNamely, electrical resistance is affected by temperatureThe higher the temperature, the higher the reistanceI can therefore provide a quick calculation based on an assumed temperatureWe'll say 100 degrees C as a nice round numberKeep in mind that that is not 100% accurate but pretty damn closeResistivity of Al 100 C : ~3.25x10^-8 ohm-meters Cross Sectional Area of 2AWG wire: 33.6 mm^2 Convert mm^2 to m^2: (mm^2)(1 m / 1000 mm)(1 m / 1000 mm) - 1 mm^2 1 um^2 1x10^-6 m^2 Therefore Cross sectional area 33.6x10^-6 m^2 Length of wire 450 feet1 meter 3.28 feet therefore 450 feet 137.2 meters RResistance in ohms eresistivity in ohm-meters Llength in meters Across sectional area in m^2 R (eL)/A R ((3.25x10^-8 ohm-meters)(137.2 meters)) / (33.6x10^-6 m^2) R 0.133 ohms 133 mOhms

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