A 4.40 mH inductor has an rms voltage of 24.9 V across it at a frequency of 230.I just can't find a formula that relates these things, yet my homework is asking it. WTF!!? help random internet people.
The peak current is when the voltage is at it's peak divided by the reactance. The peak sinusodial voltage is 29.4V * SQRT (2) 29.4V * 1.414 41.5779 V (peak) The inductive reactance is 2 * pi * Freq * L 2 * 3.1415 * 230 * 4.4 * 10E-3 6.3586 ohms Using ohms law V / R I ; 41.5779 V / 6.3586 ohms 6.5389 Amps (peak) To find the RMS voltage multiply by the square root of 2 divided by 2 or 0.707 So 6.5389 Amps * 0.707 4.6237 Amps This is also the RMS Voltage divided by the inductive reactance ! :-b
