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Question:

A 4.40-mH inductor is connected to an ac voltage source of 149.5 V rms. If the rms current in the circuit is 0?

A 4.40-mH inductor is connected to an ac voltage source of 149.5 V rms. If the rms current in the circuit is 0.880 A, what is the frequency of the source?

Answer:

Inductive Reactance X? 2πfL X E/I 149.5 / 0.880 149.5 / 0.880 2πf(4.4e-3) solve for f
X of L 149.5V/.88A 170 Ohm Frequency (X of L) / (2pi)*( L) (170 Ohm)/[(3.14)*(.0044H)] 12,305Hz

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