A 5.0 mH inductor and a 11.0 Ω resistor are connected in series with a 9 V dc battery as shown.
I'll assume an ideal inductor having no internal resistance. a) When the switch is closed at t0 the voltage across the resistor is zero. Hence, all voltage is across the inductor. V Ldi/dt 9V b) By Ohm's law nearly all voltage is across the resistor: V ir 9V after a long time. c) The resistor and inductor have the same current: i V/r 9 v / 11 ohms 9/11 A
