If the system is completely insulated from its surroundings and the final temperature of the bowl is 31.1 C, what was the mass of the block of ice? I get 19.6Kg which rounds to answer ABut the professor has the answer At 14KgWhat am I doing wrong?
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working in g, J, ?C without your work, have no idea where you went wrong Energy to warm the ice from –10 to 0, E1 2.06 J/gC x M x 10 20.6M Energy to melt the ice, E2 334 J/g x M 334 M Energy to warm the water from 0 to 31.1 E3 4.186 J/gC x M x 31.1 130.18M Energy to cool the aluminum from 300 to 31.1 E4 0.921 J/gC x 28000 x (300–31.1) 6934393 J E4 E1 + E2 + E3 M(20.6+334+ 130.18) 6934393 M 6934393 / 484.78 14300 g 14.3 kg specific heat Aluminum is 921 J/kgC specific heat of water is 4.186 kJ/kgC 4.186 J/gC specific heat of ice is 2.06 kJ/kgC 2.06 J/gC specific heat of steam is 2.1 kJ/kgK 2.1 J/gK heat of fusion of ice is 334 kJ/kg 334 J/g heat of vaporization of water is 2256 kJ/kg 2256 J/g
