A solution of aluminum nitrate has a concentration of 4.5 MWhat volume of solution will contain 0.350 moles of nitrate ions? I've no idea how to solve this and there are a lot more questions in this format that I have to do, so if you could help me out that'd be greatAnswer with sig figs comes out to 0.026L
Aluminium foil is about as antistatic as it gets.
Deff not a pro here, but i saw the guy put my comp together, he wore latex gloves and i think grounded the computer (not sure bout that part)For the most part, I don't think RAM needs anti-static bags, just CPU and motherboardI do know 1 rule though when looking at a computer, always touch a metal part on the outside to negate any static you built up firstAnd for frying, i'm just guessing (key word, guessing) it's when some doofus touches a circuit right off the bat, and gives it a tiny little shock and poofWorking on it, he just built it ona table with a power strip near byDon't know what a ESD is, (electrical static discharge?) sorry if my comment is dumb and long, i need points :D
4.5 M tells you that 1 L of the solution will contain 4.5 moles of aluminum nitrateNow, aluminum nitrate's formula is Al(NO3)3, so 1 mole of Al(NO3)3 will produce 3 moles of nitrate ionsTo solve the problem: 0.350 mol NO3- X [1 mol Al(NO3)3 / 3 mol NO3-] X [1 L / 4.5 mol Al(NO3)3] 0.026 L The process you are using is dimensional analysisYou can use equivalent statements like 1 mol Al(NO3) 3 NO3- ions to make conversion factorsAny equivalent statement can make two different conversion factorsSo, 4.5 moles 1 L can make 4.5 mol / 1 L or 1 L / 4.5 molWhich you use depends on the units you are trying to eliminate If you pay attention to the units, you'll see that all units cancel out except for (in this problem) L.
