a concrete ix requires 3 parts sand and 5 parts cement.how many pounds of cement are needed for 75 pounds of sand?
...the conventional blend for concrete is 3 parts gravel 2 parts sand and a million area cement....all of this by quantity not weight purely as Russell states...my answer replaced into incorrect and that i replaced it because i remerbered weight had not something to do with the blend...i had the combination instructions good purely had the burden pasrt incorrect..
3 parts sand:5 parts cement 75 # sand 75#/3=x/5 x=75*5/3=125# of cement.
The cement/sand ratio is 5 to 3 or 5/3 which equals a ratio of 1.67/1. Multiply the mass of the sand by 1.67. You need 125 lbs of cement
Cement : sand = 5 : 3 So 3 parts = 75 pounds So 1 part = 25 pounds Thus cement needed = 5 parts = 125 pounds
