...the crate weighs 4000N when resting on the ground. Find the followinga)The tension in the cable necessary to do thisb)The work done by the cablec)The work done by gravityd)The total work done by the systeme)The final velocity of the crate
One-fifth of a g is 1.96 m/s?. The mass of the crate is... m = F / a = 4,000 N / 9.8 m/s? = 408 kg The force of the crane must be greater than that of the force of gravity. The acceleration must therefore greater as well. 9.8 m/s? + 1.96 m/s? = 11.8 m/s? a) T = ma = 408 kg x 11.8 m/s? = 4.81 x 10^3 N b) W = Fd = (4.81 x 10^3 N) x 25.0 m = 1.20 x 10^5 J c) W = Fd = 4,000 N x 25.0 m = 1.00 x 10^5 J d) W (total) = W (crane) + W (gravity) = (1.20 x 10^5 J) + (1.00 x 10^5 J) = 2.20 x 10^5 J e) v (final) = (v? + 2a?x)^(1/2) = ((0 m/s)? + (2 x 1.96 m/s? x 25.0 m))^(1/2) = 9.90 m/s I'm sure that all of my answers are correct. If anything is incorrect, please e-mail me again. Best of luck to you Jim.
Ghee is clarified butter! The rest sounds like homework!
