A few questions about LED lights
First, the power supply current exceeds the LED light source of the load current, lead to LED lamp bead light failure quickly, even destroyed. Solution: 1, to reduce the input current; 2, the LED light source for more than 45 mil 3 w light bead, so each lamp bead to withstand current of 700 ma, but this time is 9 w, must increase the radiator. Second, the high voltage is bound to burning lamp bead,, the only way to avoid lower voltage, series resistance. Third, voltage and current are beyond ratings, is sure to burn, not saved. Can only cut down the voltage and current are. Method is still the same, want to directly change the power supply, either in LED series resistance voltage drop flow in the circuit
1 power supply voltage must be the same as the load, the power of the output current is larger, can provide the greater the power, the power of the load ability is stronger, so the output voltage of 12 v, the power of the output current of 700 ma can be used for you to shoot the light. Of course, if a larger output current of the power supply can also use just a little too wasted. 2 and 3 for the power supply voltage of 24 v, most likely have to burn the load (leds and circuit component), if want to use, with a voltage divider to be available 24 v down to 12 v. 2 the output current and load is the same, but actually does not reach 350 after partial pressure and loss ma output, so 2 after decompression can not use or scrape can be used. 3 the same supply voltage is too high to buck can use until about 12 v, otherwise it will burn, 700 ma output current can meet the requirements of shoot the light. Summary: the power of the output current must load than old do line, otherwise due to the load is too heavy to burn the power supply, power supply voltage and load the same or close to, can have a little error, but the difference is too large, high voltage too much, may burn load circuit and LED (lamp), is too low, could not move or inefficient work load and the load is not work.
1, the power supply can be theoretically the two sets of 3 w shoot the light, the output current is greater than work, but not small, not to shoot the light burning 2, the 24 v power supply can shoot the light series two such use, single pick up a 12 v lamp will certainly out of the question, the output voltage must be consistent with working voltage 3, similar to the second question, this problem only output current is bigger, can't meet, but can be parallel two groups of two series of a total of four series lamp or two to shoot the light.
