determine the maximum load the crane can support in kg if the bending moment on the beam is not to exceed 5000 Nm and the shear force is not to exceed 3KN when the crane is positioned at mid span
figure shear first Let F be the max. crane load. for a simply supported symmetric load, the reactions at each end support will be half the total load. The reaction loads will also equal the shear load. 3000 N = (F + 150(9.8))/2 F = 4530 N The maximum bending moment will be the shear force times the moment arm of half the joist length 5000 Nm = [(F + 150(9.8))/2] N (2.0 m) 5000 = F + 150(9.8) F = 3530 N The bending moment max load is 1000 N less than the Shear max load so bending is the limiting factor The maximum load allowed is F = 3530 N 3530 / 9.8 = 360 kg As a form of exchange, please remember to vote a Best Answer from your results.
