An inductor coil of 1H carrying a current of 2A in the circuit . To prevent sparking , when the current is switched off a capacitor which can withstand a potential difference of 400 V is used . What must be the minimum capacitance ?Please show the working steps .
NOTE: that is a LARGE inductor and a LARGE current. The energy of the magnetic field in the inductor is the following: MPE 1/2*L*I^2 This energy will be conserved when it is dis-current-ed in to charging the capacitor. MPE EPE EPE 1/2*C*V^2 Substitute: 1/2*L*I^2 1/2*C*V^2 Solve for C: C L*I^2/V^2 Calculate: C25 microfarads
