A sample of iron ore weighing 2.80g is to be analyzed for the percentage of iron. All of the iron in the sample is converted into iron oxide (Fe2O3) which has a mass of 1.00g. What is the percentage of iron in the ore?Please show all steps. Thanks :)
alignment has nothing to do with balancing. probably what happened was the tires were out of balance before you got the alignment and you could,nt tell because it was out of alignment.
If your tires are worn uneven its due to alignment. Balancing issues are when tires are shaking while rotating.
Well you should not align with worn tires. You should either leave and wait for tires to be worn out and get new ones and then that is the time for alignment of Welles. Tire balancing wont do anything really. New tires is best bet.
1) Calculate the percentage of Fe in Fe2O3 Fe: 2 x 55.8 111.6 O: 3 x 16.0 48.0 Total 159.6 % Fe 111.6 / 159.6 % Fe 0.699 69.9 % 2) You have 1.00 g of Fe2O3, and 69.9 % of that is Fe 69.9 % of 1.00 g 0.699 g Fe, which came from the ore. 3) The original sample was 2.80 g and now you know that 0.699 g of that is Fe. The percent Fe is the original sample is 0.699 g / 2.80 g 0.2496 25.0 %
