Her mass is 54.0 kg, and the combined mass of the elevator and scale is an additional 815 kg. Starting from rest, the elevator accelerates upward. During the acceleration, the hoisting cable applies a force of 9470 N. What does the scale read during the acceleration?
the scale reads the normal force acting on it, so we have N- mg = ma where mg is the weight of the system and ma is the acceration of the system we find that acceleration from F=ma or a=F/m where F=9050N and m=778.5kg a=11.6m/s/s therefore, N=m(g+a)=778.5kg(9.8+11.6)m/s/s = 1.67x10^4N
This Site Might Help You. RE: A woman stands on a scale in a moving elevator. ? Her mass is 54.0 kg, and the combined mass of the elevator and scale is an additional 815 kg. Starting from rest, the elevator accelerates upward. During the acceleration, the hoisting cable applies a force of 9470 N. What does the scale read during the acceleration?
Weight of person and elevator is (815+54)*9.8 = 8516 N hoist provides net upwards force of 9470 - 8516 = 954 N This provides an upwards acceleration of F = ma 954 = (815+54) a a = 1.10 m/s? This subtracts from the normal 9.8 m/s?, so net acceleration is 9.8 - 1.1 = 8.7 m/s? what percent of g is this? 8.7/9.8 = 89% So the scale would read 89% of 54 = 48 kg, assuming scale is calibrated in kg. ,
