Question:
an energy of 1.80x10^2 kj/mol is required to cause an aluminum atom on a metal surface to lose an electron.?
Calculate the lowest wavelength of light in nanometers that can ionize an aluminum atom.
Answer:
my friend crawled into my bed and started sucking on my toesstraaaaaaange dreams
I crawled out a window, peed in the bushes, crawled back in, pulled my best friend off the couch onto the floor and took her place.
I went to pee in the bathtub when I was littleLucky my Dad guided me to the toilet, but I woke up half-way done and was so confusedOnce I was dreaming I was investigating a murder of a young girl and interrogated my mum while she was making sandwiches for school at 5amLOL.
I used to sleepwalkBut, I would only get so far as the corner in my bedroom and I would just stand there staring into space until I finally woke upNeedless to say, it made my teenage slumber parties quite the experience :)
Use the following equation: Ehf + (1/2)m(v^2) where, E is the energy, h is the Plank's constant, f is the threshold frequency, m is the mass of electron, v is the velocity of the electron after it is released from the atomIn the question, given values are: E 1.80 10^2 10^3 J/mol but energy required for an atom to lose an electron is E/N 1.80 10^5 / [6.022 10^(23)] J, where N is the Avogadro's numberh 6.62 10^(-34) kg m^2 s^(-1) Since v0m/s, the equation reduces to: energy hf f {1.80 10^5 / [6.022 10^(23)]} / [6.62 10^(-34)] Now wavelength c/f (where c is the speed of light, 3 10^8 m/s) Substituting the values of c and f in the above equation, we get the value of wavelength 6.64 10^(-7) m 6.64 10^2 nm
my friend crawled into my bed and started sucking on my toesstraaaaaaange dreams
I crawled out a window, peed in the bushes, crawled back in, pulled my best friend off the couch onto the floor and took her place.
I went to pee in the bathtub when I was littleLucky my Dad guided me to the toilet, but I woke up half-way done and was so confusedOnce I was dreaming I was investigating a murder of a young girl and interrogated my mum while she was making sandwiches for school at 5amLOL.
I used to sleepwalkBut, I would only get so far as the corner in my bedroom and I would just stand there staring into space until I finally woke upNeedless to say, it made my teenage slumber parties quite the experience :)
Use the following equation: Ehf + (1/2)m(v^2) where, E is the energy, h is the Plank's constant, f is the threshold frequency, m is the mass of electron, v is the velocity of the electron after it is released from the atomIn the question, given values are: E 1.80 10^2 10^3 J/mol but energy required for an atom to lose an electron is E/N 1.80 10^5 / [6.022 10^(23)] J, where N is the Avogadro's numberh 6.62 10^(-34) kg m^2 s^(-1) Since v0m/s, the equation reduces to: energy hf f {1.80 10^5 / [6.022 10^(23)]} / [6.62 10^(-34)] Now wavelength c/f (where c is the speed of light, 3 10^8 m/s) Substituting the values of c and f in the above equation, we get the value of wavelength 6.64 10^(-7) m 6.64 10^2 nm
