In refining 100 g of the ore, 72.35 g of iron are obtained. What is the empirical formula of the ore?
LOL. If they're going to tell you that it is magnetite, then the formula is Fe3O4, iron(II) (III) oxide. Otherwise, you can convert the masses of iron and oxygen into moles and then find the whole-number mole ratio. 72.35g Fe x (1 mol Fe / 55.8 g Fe) 1.30 mol Fe / 1.30 1 x 3 3 27.65 g O x (1 mol O / 16.0 g O) 1.73 mol O / 1.30 1.33 x 3 4 Fe3O4
The empirical formula of magnetite is Fe3O4.
