An iron ore sample contains Fe2O3, and reaction of the ore with CO produces iron metal: Fe2O3+ 3CO --gt;2Fe + 3CO2 is the balanced equation. 1) Calculate the number of grams of CO that can react with .150 kg of Fe2O3.2) Calculate the number of grams of Fe and the number of grams of CO2 formed when .150 kg of Fe2O3 reacts.
Nuff Said, I Just did not know the why of it.
% by mass of Fe2O3 (mass of pure Fe2O3 / mass of iron ore) x 100% mass of Fe2O3 (pure) (mass of iron produced / MW of iron) x ( stoichiometric mole ratio of Fe2O3 over Fe based on the given chemical reaction x MW of Fe2O3 mass of iron produced 453 g MW of Fe 55.85 stoichiometric mole ratio of Fe2O3/Fe 1/2 MW of Fe2O3 159.7 mass of pure Fe2O3 (453/55.85) x (1/2) x 159.7 mass of pure Fe2O3 647.66 grams %by mass of Fe2O3 (647.66 / 752) x 100 86.13 %
Fe2O3+ 3CO --2Fe + 3CO2 M.W. of Fe2O3160 g/mol 1) # of moles of Fe2O3150g/160g/mol0.9375 mol # of moles of CO reacting with 0.9375mol of Fe2O30.9375 mol*3 2.8125mol M.W.of CO28 g/mol # of Grams of CO required1.875 mol* 28 g/mol78.75 g M.W. of Fe56 g/mol 2)# of moles of Fe produced0.9375 *2mol1.875 mol # of Grams of Fe produced1.875 mol*56 g/mol105 g M.W. of CO244 g/mol # of moles of CO2 produced0.9375*3 mol2.8125 mol # of Grams of CO2 produced2.8125 *44g/mol123.75 g
