An RLC circuit contains a 4.100e-6 F capacitor in series with an inductor. What should the value of the inductance be for a resonance frequency of 63.0 rad/s?Do we have to have the Equivalence Capacitance as 1/C, since the capacitor is in series?The formula for Resonance frequency is: omega 1 / (SQRT(L*C))where L ImpedanceC Capacitancebut Capacitance in series would be 1/4.1E-6 F which equals 2.44E5 F.Is this correct so far?OK if so, solving the resonance frequency for L would give: L 1 / C* omega^2omega 63 rad/s soomega^2 3969 rad/sso1 / (2.44E5 * 3969) 1.033E-9is right?! PLEASE HELP!!
Capacitive reactance, Xc 1/WC Inductive reactance, XL WL At resonace the capacitive and inductive reactance are equal. Xc XL Therefore, 1/W x C WL L 1/(W^2 x C) L 1/(63 x 63 x 4.1 x 10^-6) L 61.45 H. Wow! that's a big inductor. Are you sure W is correct?
