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Question:

At a given instant the current through an inductor is 15.5 mA and is increasing at the rate of 270 mA/s .?

A) What is the initial energy stored in the inductor if the inductance is known to be 66.5 mH ?B)How long does it take for the energy to increase by a factor of 9 from the initial value?Please give me final answer too :x thank you so much!

Answer:

Energy stored in the inductor 1/2 Li? 1/2 x 66.5x10?? x (15.5x10??)? 7988.3125 x 10?? J 7.988 x 10?? J W ∝ i? Hence for energy to become 9 times, the current flowing through the inductor should increase by √9 3 times. That is current should be 3 x 15.5 46.5mA Time taken (46.5 - 15.5) / 270 0.1148s

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