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Question:

At a given instant the current through an inductor is 50.0mA and is increasing at the rate of 115 mA/s?

At a given instant the current through an inductor is 50.0mA and is increasing at the rate of 115 mA/s. What is the initial energy stored in the inductor it the inductance is known to be 60.0mH, and how long does it take for the energy to increase by a factor of 10 from the initial value?

Answer:

Energy in an inductor 0.5 L I^2 0.5 (60 x10^-3)(50 x10^-3)^2 7.5 x10^-5 J 7.5 x10^-4 J 0.5 (60 x10^-3) I^2 I SQRT [ 7.5 x10^-4 J / 0.5 (60 x10^-3) ] 1.58 x10^-1 Amps 158mA increase needed 158mA - 50mA 108mA time 108mA /115mA/s .939 sec

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