it‘s for a physics presentation about the impulse eqaution related to professional motorcycle racing:[ F(?t) m(Vf – Vi)] weight of motorcycle: 148kgweight of rider: 63kgVi:320km/hVf:105km/hspace of braking:338metersTime of braking:6.4secwith the impulse equation will i calculate the forces on the rider or the bike?do i have to solve for F to get the forces i need to show?do these forces come out to be in Newton or some other label?i‘m sorry for my english it‘s not my first language and i find physics very hard!!!
Think of the rider and bike as one thing. and *sigma*F ma is all you need to get the force due to acceleration. EF 211kg*a a (Vf - Vi)/t a 59.7222./6.4(if you want newtons you need to convert the units) a -9.332 m/s^2 EF 211kg*-9.332 m/s^2 EF 1968.97Newtons being exerted on the bike and rider.
all forces are newton forces,they are further classified thoforce basically was created by newton to explain mechanics,its just like maths,before someone wrote 2+24 it wasn't called addition.so it is just a convention.to call it force or newton's force You have to calculate the net force on the cycle of which part of it goes into stopping the rider. F(6.4)63(320-105).5/18 we are assuming a lot of stuff thoso its useless if u use the same equation in reality.
all forces are newton forces,they are further classified thoforce basically was created by newton to explain mechanics,its just like maths,before someone wrote 2+24 it wasn't called addition.so it is just a convention.to call it force or newton's force You have to calculate the net force on the cycle of which part of it goes into stopping the rider. F(6.4)63(320-105).5/18 we are assuming a lot of stuff thoso its useless if u use the same equation in reality.
Think of the rider and bike as one thing. and *sigma*F ma is all you need to get the force due to acceleration. EF 211kg*a a (Vf - Vi)/t a 59.7222./6.4(if you want newtons you need to convert the units) a -9.332 m/s^2 EF 211kg*-9.332 m/s^2 EF 1968.97Newtons being exerted on the bike and rider.