Can someone give me a brief run through of how to calculate soil excavation as my searching on the net is proving unsuccessful. The area is 180x60x6 which equals 64800m3. The bulk factors are 1.3 for clay and 1.15 for fill material. The excavator has a peak output of 180 cubic meters per hour.What is the sum to incorporate the bulking factors into the equation to get a more realistic load of soil that needs to be excavated.Thanks
It seems the question is not complete, I think the ratio of clay and fill material is required, the bulk factors here is the clay density which is 1300 kg/m^3 , and fill material is 1150 kg/m^3 . As the total soil volume is 64800 m^3 and excavator efficiency is 180 m^3 per hour , then the total time is 64800/180 = 360 hours
